What volume will the nitric oxide (4) obtained by the interaction of 2 mol of nitric oxide (2) and 1.5 mol of oxygen take?

Given:
n (NO) = 2 mol
n (O2) = 1.5 mol
Vm = 22.4 l / mol

To find:
V (NO2) -?

Decision:
1) Write the equation of a chemical reaction:
2NO + O2 => 2NO2;
2) The amount of NO substance is in short supply, therefore, calculations will be carried out for it;
3) Determine the amount of the substance NO2 (taking into account the coefficients in the reaction equation):
n (NO2) = n (NO) = 2 mol;
4) Calculate the volume of NO2 (under normal conditions):
V (NO2) = n (NO2) * Vm = 2 * 22.4 = 44.8 liters.

Answer: The volume of NO2 is 44.8 liters.