What volumes of chlorine and hydrogen are required to obtain hydrochloric acid weighing 200 g

What volumes of chlorine and hydrogen are required to obtain hydrochloric acid weighing 200 g, with a mass fraction of acid of 18.25%?

The reaction of obtaining hydrochloric acid.
The mass of the acid in the solution is.
m (HCl) = m (solution) • W (HCl) / 100% = 200 g • 18.25% / 100% = 36.5 g.
The number of moles of hydrochloric acid.
n (HCl) = m / Mr = 36.5 g / 36.5 g / mol = 1 mol.
According to the reaction equation, two times more acid is formed, which means the amount of moles of hydrogen and chlorine is.
n (H2) = n (Cl2) = n (HCl) / 2 = 1 mol / 2 = 0.5 mol.
The volumes of gases will be equal.
V (H2) = V (Cl2) = n • Vm = 0.5 mol • 22.4 l / mol = 11.2 l.