What volumes of hydrogen and nitrogen will be required to obtain such an amount of NH3

| September 1, 2021 | education

What volumes of hydrogen and nitrogen will be required to obtain such an amount of NH3, when interacting with an excess of HNO3, 20 g of salt is obtained?

1. We write down the equation of reactions.
NH3 + HNO3 → NH4NO3.
We find the mass of ammonia according to the reaction equation.
M (NH3) = 14 + 1 × 3 = 17 g / mol.
M (NH4NO3) = 14 + 4 + 14 + 48 = 80 g / mol.
X g NH3 – 20 g NH4NO3.
17 g / mol NH3 – 80 g / mol NH4NO3.
X = 17 × 20: 80 = 4.25 g NH3.
Find the molar mass of ammonia.
n = m / M.
n = 4.25 / 17 = 0.25 mol.
2. We write down the equation of reactions.
N2 + 3H2 = 2NH3.
We find the amount of the substance nitrogen and hydrogen.
X mol N2 – 0.25 mol NH3
1 mol N2 – 2 mol NH3
X = 1 × 0.25: 2 = 0.125 mol.
V = n × Vm = 0.125 mol × 22.4 L / mol = 2.8 L N2.
X (H2) = 3 × 0.125: 2 = 0.1875 mol.
V (H2) = 0.1875 mol × 22.4 L / mol = 4.2 L.
Answer: the volume of nitrogen is 2.8 liters; the volume of hydrogen is 4.2 liters.



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