What was the initial train rate, if 40 s, moving with an acceleration of 0.06m / s2, it reached the speed of 3m / s?
| June 28, 2021 | education
These tasks: T (the duration of the train with acceleration) = 40 s; a (acceleration) = 0.06 m / s2; V (the speed that the train reached) = 3 m / s.
The initial velocity of the subsidence can be expressed from the formula: V = V0 + A * T and V0 = V – A * T.
Calculation: V0 = 3 – 0.06 * 40 = 3 – 2.4 = 0.6 m / s.
Answer: Before acceleration, the train was moving at a speed of 0.6 m / s.
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