What was the temperature on the ground if at a depth of 1320 meters – + 52 degrees?

To solve the problem, you first need to indicate the geothermal temperature gradient, which shows the change in temperature for every 100 meters of depth.

On average, it is 2.5 to 3 degrees Celsius for every 100 meters.

We assume a temperature gradient of 3 degrees Celsius.

In this case, we get:

1320/100 * 3 = 39.6 degrees. (The temperature at a given depth is that much higher than at the surface.)

Find the temperature on the surface.

52 – 39.6 = 12.4 degrees Celsius.