What way did a car weighing 1500 kg travel if it was moving at a speed of 36 km / h

What way did a car weighing 1500 kg travel if it was moving at a speed of 36 km / h and stopped at the end of an even slow motion? the coefficient of friction is 0.5

Task data: m (vehicle weight) = 1500 kg; V0 (the speed of the vehicle in question before the start of braking) = 36 km / h (in the SI system V = 10 m / s); μ (coefficient of friction) = 0.5.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

1) Determine the constant acceleration of the vehicle under consideration: m * a = Fcopr = μ * m * g, whence a = μ * g = 0.5 * 10 = 5 m / s2.

2) Calculate the distance traveled: S = (V0 ^ 2 – V ^ 2) / 2a = (10 ^ 2 – 0) / (2 * 5) = 10 m.

Answer: The car in question has traveled 10 m.