What will be the final temperature if ice weighing 500 g at a temperature of 0 degrees is immersed in 4 liters

What will be the final temperature if ice weighing 500 g at a temperature of 0 degrees is immersed in 4 liters of water at a temperature of 30 degrees?

Given:
m1 = 500 g = 0.5 kg
m2 = 4 l = 4 kg
t1 = 30 ° C
t2 = 0 ° C
L = 330,000 J / kg
c = 4200 J / kg * K
Find: T -?
Decision:
Q = Lm
Q = cm (t2-t1)
Q = 33 * 10 ^ 4 * 0.5 = 165,000 J = 165 kJ
Q = cmdT
Q = 4200 * 4 * 1 = 16800 J
Now let’s find the temperature change during ice melting: 165,000/16800 = 9.8 ° С
Find the temperature change: 30 – 9.8 = 20.2 ° С
T = 20.2 * 8/9 = 18 ° C
Answer: 18 ° C