What will be the gas pressure after cooling from 30 to 0 С, if at 30 С the gas pressure
| September 6, 2021 | education
What will be the gas pressure after cooling from 30 to 0 С, if at 30 С the gas pressure was equal to 2 * 10 ^ 5 Pa. The molar mass of air is 0.029.
t1 = 30 ° C.
t2 = 0 ° C.
P1 = 2 * 10 ^ 5 Pa.
M = 0.029 kg / mol.
V1 = V2.
P2 -?
We will assume that the gas is cooled at a constant volume V1 = V2, that is, isochoric. Charles’s law is valid for the isochoric process: P1 / T1 = P2 / T2.
For a constant gas mass with its volume unchanged, the ratio of the gas pressure P to its absolute temperature T is a constant: P / T = const.
P2 = P1 * T2 / T1.
T1 = 273 + t1 = 273 + 30 = 303 ° K.
T2 = 273 + t2 = 273 + 0 = 273 ° K.
P2 = 2 * 10 ^ 5 Pa * 273 ° K / 303 ° K = 1.8 * 10 ^ 5 Pa.
Answer: after cooling, the gas pressure was P2 = 1.8 * 10 ^ 5 Pa.
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