What will be the mass fraction of sugar in the compote if it contains 0.14 mol of sucrose per 14 mol of water?

Let’s write down given:

n (H2O) = 14 mol

n (C12H22O11) = 0.14 mol

W (C12H22O11) -?

Solution:

1) Calculate the mass of water:

M (H2O) = 18 g / mol

m = n * M

m (H2O) = 18 g / mol * 14 mol = 252 g

2) Calculate the mass of sucrose in solution:

M (C12H22O11) = 12 * 12 + 22 * 1 + 16 * 11 = 342 g / mol

m (C12H22O11) = 342 g / mol * 0.14 mol = 48 g

3) Calculate the mass fraction of sucrose in the solution:

m (solution) = 252 g (H2O) + 48 g (C12H22O11) = 300 g

W (C12H22O11) = m (C12H22O11) * 100% / m (solution)

W (C12H22O11) = 48 g * 100% / 300 = 16%

Answer: W (C12H22O11) = 16%