What will be the number of a member of the arithmetic progression equal to 53, if a1 = -4; d = 3?

Let’s write down the formula for finding the nth term of the arithmetic progression.

an = a1 + (n – 1) d. With a1 = – 4 and d = 3, the expression will take the form:

– 4 + (n – 1) * 3 = 53.

– 4 + 3n – 3 = 53.

– 7 + 3n = 53.

n = (53 + 7): 3 = 60: 3 = 20.

Answer: the twentieth term of this progression is 53.



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