What will be the phenotypic cleavage in the offspring resulting from the crossing of black (A) furry (B)

What will be the phenotypic cleavage in the offspring resulting from the crossing of black (A) furry (B) guinea pigs, heterozygous for two traits linked in one chromosome?

If you cross black (A) and hairy (B) guinea pigs, which are heterozygous for 2 traits, obtained in one chromosome, then you can find out what the phenotype will be in the offspring. Let’s take a closer look at the crossing process:
From the condition we get that if the genes of black and furry guinea pigs are linked in one chromosome, then only 2 types of gametes can turn out.
P: AB / ab * AB / ab
G: AB, ab – from the first individual and AB, ab – from the second individual.
F1: we get the genotype splitting: 1AABB, 2AaBb, 1aabb – this ratio is like 1: 2: 1
that is, the phenotype splitting will be 3: 1
Answer: 3: 1 phenotype cleavage