What will be the speed of a body weighing 5 kg, moving at a speed of 8 m / s, if at a distance of 10 m, a force F = 12 N
What will be the speed of a body weighing 5 kg, moving at a speed of 8 m / s, if at a distance of 10 m, a force F = 12 N will act on the body, the direction of which coincides with the direction of movement
m = 5 kg.
V1 = 8 m / s.
S = 10 m.
F = 12 N.
V2 -?
According to 2 Newton’s law, if a constant force F acts on a body, then it moves with a constant acceleration a, the value of which is determined by the formula: a = F / m.
With uniformly accelerated motion, the acceleration of the body a is determined by the formula: a = (V2 ^ 2 – V1 ^ 2) / 2 * S.
F / m = (V2 ^ 2 – V1 ^ 2) / 2 * S.
V2 ^ 2 – V1 ^ 2 = F * 2 * S / m.
V2 ^ 2 = F * 2 * S / m + V1 ^ 2.
V2 = √ (F * 2 * S / m + V1 ^ 2).
V2 = √ (12 N * 2 * 10 m / 5 kg + (8 m / s) 2) = 10.6 m / s.
Answer: the speed of the body will become V2 = 10.6 m / s.