What will the dynamometer reading be if a 150cm ^ 3 weight is immersed in gasoline? Weight in the air 10N.

1) A buoyant force F = ρVg will act on a weight immersed in gasoline. ρ is the density of gasoline, we find its value in the reference book: ρ = 710 kg / m2.
2) We calculate the value of the buoyancy force (the volume is preliminarily converted to m3: V = 150 cm3 = 0.00015 m3): F = (710 kg / m3) * (0.00015 m3) * (10 m / s2) = 1.065 N.
3) The dynamometer reading P will be equal to the difference between the weight of the weight in air and the buoyancy force, that is, P = 10 N – 1.065 N = 8.935 N.
ANSWER: P = 8.935 N.