What will the dynamometer show if you hang a 200 cm3 lead weight on it with a lead density of 11340 kg / m3?

Given:

V = 200 cm ^ 3 = 0.0002 m ^ 3 – the volume of the lead weight;

ro = 11340 kilogram / cubic meter – lead density;

g = 10 m / s ^ 2 – acceleration of gravity.

It is required to determine the weight of the lead weight P (Newton).

Let’s find the mass of the lead weight:

m = ro * V = 11340 * 0.0002 = 2.3 kilograms.

Then the weight of the lead weight will be equal to:

P = m * g = 2.3 * 10 = 23 Newtons.

Answer: the dynamometer will show a weight equal to 23 Newtons.