What will the gas pressure be when it is compressed from 8 to 5 liters if the initial pressure is 100 kPa?

V1 = 8 liters = 0.008 m ^ 3 – initial gas volume;

V2 = 5 liters = 0.005 m ^ 3 – final gas volume;

P1 = 100 kPa = 100000 Pascal – initial gas pressure.

It is required to determine P2 (Pascal) – the final gas pressure.

Since the condition of the problem is not specified, we assume that the compression process took place isothermally, that is, at a constant temperature. Then:

V1 * P1 = V2 * P2, hence:

P2 = V1 * P1 / V2 = 0.008 * 100000 / 0.005 = 800 / 0.005 = 160000 Pascal = 160 kPa.

Answer: after compression, the gas pressure will be 160 kPa.