What work did an ideal gas do, expanding at a constant pressure of 100 kPa, if its volume

What work did an ideal gas do, expanding at a constant pressure of 100 kPa, if its volume changed from 2 liters to 3 liters?

These tasks: P (constant pressure of the taken ideal gas when performing work) = 100 kPa (100 * 10 ^ 3 Pa); V1 (initial volume) = 2 l (2 * 10 ^ -3 m3); V2 (volume of gas taken after expansion) = 3 liters (3 * 10 ^ -3 m3); isobaric process.

The work of the taken ideal gas in the process of its isobaric expansion is calculated by the formula: A = P * ΔV = P * (V2 – V1).

Let’s perform the calculation: A = 100 * 10 ^ 3 * (3 * 10 ^ -3 – 2 * 10 ^ -3) = 100 J.

Answer: The ideal gas taken should have done a work of 100 J.