What work did the electric current do in 10 minutes of operation of a 500 W boiler when heating water?
| September 23, 2021 | education
Data: t (duration of the boiler operation) = 10 min (600 s); N (power of the boiler taken) = 500 watts.
The work done by the electric current will be equal to the product of the power of the boiler and the time of its operation: A = N * t.
Let’s calculate: A = 500 * 600 = 300000 J or 300 kJ.
Answer: The useful work of the electric current was 300 kJ.
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