What work does a car engine do on a path of 80 meters, developing a traction force of 6.5 thousand N.

As we know from the school physics course, the work that the engine does can be calculated using the following formula:

A = F * s, where F is the thrust that the engine develops, and s is, in fact, the distance that it travels.

Let us determine what value the work will be equal to, what the engine does, covering a distance of 80 meters, if from the condition of our problem we know for sure that the traction force at this time is equal to 6500 N:

A = 6500 * 80 = 520000.

Answer: 520000 J.