What work does gravity do when a load of 1 ton is evenly lifted to a height of 50 m?

These tasks: the movement of the load is uniform; m (mass of the lifted load) = 1 t (in SI m = 1 * 10 ^ 3 kg); h (lifting height) = 50 m.

Constants: g (acceleration due to gravity) ≈ 10 m / s2.

The work that, with a uniform lifting of the taken load, was performed by the force of gravity, we define by the formula: A = Fт * S * cosα = m * g * h * cosα.

Let’s calculate: A = 1 * 10 ^ 3 * 10 * 50 * cos180º = -500 * 10 ^ 3 J (-500 kJ).

Answer: The work of gravity when lifting the taken load is equal to -500 kJ.