What work does the electric field do in the section of the conductor with a voltage of 0.04 kV

What work does the electric field do in the section of the conductor with a voltage of 0.04 kV when the charge moves 5 mC?

To determine the work that the electric field should have done, we apply the formula: A = q * Δφ = q * U, where q is the charge displaced by the considered field (q = 5 mC = 5 * 10-3 C); U is the voltage on the conductor section (U = 0.04 kV = 40 V).

Let’s calculate: A = q * U = 5 * 10-3 * 40 = 0.2 J.

Answer: To move a charge of 5 mC, the considered electric field must do a work of 0.2 J.