What work does the field do when a 4nC charge moves from a point with a potential of 250V

What work does the field do when a 4nC charge moves from a point with a potential of 250V to a point with a potential of 50V?

As we know from the school physics curriculum, the work of an electrostatic field on a charge can be calculated by using the following formula:

A = q * (φ1 – φ2), where q is the electric charge, φ1 is the potential value at the initial point, and φ2- is, respectively, the potential value at the final point:

Let us determine what value will be equal to the work that was done by the field in our case:

4 nC = 4 * 10-9 C;

4 * 10-9 * (250 – 50) = 8 * 10-7 J.

Answer: 8 * 10-7 J.