What work does the gas do, expanding at a constant pressure of 3 atmospheres from 3 liters to a volume of 18 liters.

To find out the work that the specified gas must perform, consider the formula: Ax = P * (V – V0), where P is constant pressure (P = 3 atm. ≈ 0.3 * 10 ^ 6 Pa); V – volume after expansion (V = 18 l = 18 * 10 ^ -3 m3); V0 – volume before expansion (V = 3 l = 3 * 10 ^ -3 m3).

Let’s perform the calculation: Ax = P * (V – V0) = 0.3 * 10 ^ 6 * (18 * 10 ^ -3 – 3 * 10 ^ -3) = 4.5 * 10 ^ 3 J.

Answer: The work done by the indicated gas is 4.5 kJ.