What work does the pump do in one hour, if every minute it throws 1200 liters of water to a height of 24 m?

Data: t (required duration of the pump operation) = 1 h (60 min); t1 (duration of water discharge) = 1 min; V (volume of ejected water during time t1) = 1200 l (1.2 m3); h (discharge height) = 24 m.

Constants: g (acceleration of gravity) = 9.81 m / s2; ρ (water density) = 24 m.

The work that the pump will perform in 1 hour is determined by the formula: A = F * s = m * g * h = ρ * V * t * g * h.

Calculation: A = 1000 * 1.2 * 60 * 9.81 * 24 = 16951680 J ≈ 16.95 MJ.

Answer: The pump will do work of 16.95 MJ.