What work does the pump do in one hour if every minute it throws 1200 liters of water to a height of 24 meters?

| February 12, 2021 | education

To find the work produced by the specified pump, we will use the formula: A = P * S * t = m / t1 * g * Δh * t = ρw * V / t1 * g * Δh * t.

Const: q – acceleration of gravity (q ≈ 9.8 m / s2); ρw is the density of the ejected water (ρw = 103 kg / m3).

Data: V – volume of ejected water (V = 1200 l / min = 1200 dm3 / min = 1.2 m3 / h); t1 – known operating time (t1 = 1 min); Δh – lifting height (Δh = 24 m); t is the time under consideration (t = 1 h = 60 min).

Let’s make a calculation: A = ρw * V / t1 * g * Δh * t = 10 ^ 3 * 1.2 / 1 * 9.8 * 24 * 60 = 169.34 * 10 ^ 3 J ≈ 16.9 MJ.

Check: [J] = kg / m3 * m3 / min * m / s2 * m * min = kg * m3 * m * m * min / (m3 * min * s2) = kg * m2 / s2 (correct).

Answer: For 1 hour, the work of the specified pump will be 16.9 MJ.



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