What work is done by the force of gravity acting on a raindrop weighing 20 * 10 ^ -6

What work is done by the force of gravity acting on a raindrop weighing 20 * 10 ^ -6 kg when it falls from a height of 2 km?

h = 2 km = 2000 m.

m = 20 * 10-6 kg.

g = 10 m / s2.

A -?

The mechanical work A of the force F is determined by the formula: A = F * S * cosα, where S is the movement of the body under the action of the force, ∠α is the angle between the direction of action of the force F and the movement of S.

The force of gravity F is always directed vertically downward and is determined by the formula: F = m * g.

The movement of the drop S is also directed vertically downward and is equal to the drop height h: S = h.

Since gravity and displacement are directed equally vertically downward, then ∠α = 0 °, cos0 ° = 1, The mechanical work of gravity will be determined by the formula: A = m * g * h.

A = 20 * 10-6 kg * 10 m / s2 * 2000 m = 0.4 J.

Answer: when a drop falls, gravity performs mechanical work A = 0.4 J.