What work must be done in order to evenly lift a load weighing 1.5 g from a mine 400 m deep.
| June 2, 2021 | education
Given: h (shaft depth) = 400 m; m (mass of the load evenly lifted from the mine) = 1.5 t (in SI m = 1500 kg).
Constants: g (acceleration due to gravity) ≈ 10 m / s2.
The work that needs to be done to lift the load from the mine is calculated by the formula: A = ΔEp = m * g * h.
Calculation: A = 1500 * 10 * 400 = 6 * 10 ^ 6 J (6 MJ).
Answer: To lift a load, it is necessary to perform a work of 6 MJ.
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