What work needs to be done to evenly lift a load weighing 15 tons to a height of 40 m.

m = 15 t = 15000 kg.

g = 10 m / s2.

h = 40 m.

A – ?

Mechanical work A is called a scalar physical quantity, the value of which is determined by the formula: A = F * S * cosα, where F is the force that acts on the body, S is the displacement of the body, ∠α is the angle between the direction of action of the force F and displacement S.

Since the load is lifted evenly, then, according to 1 Newton’s law, F = m * g.

S = h.

A = m * g * h * cosα.

Since the force with which the load is lifted is directed vertically upward and the body moves vertically upward, then ∠α = 0 °, cos0 ° = 1.

A = 15,000 kg * 10 m / s2 * 40 m = 6,000,000 J.

Answer: when lifting the load, work is performed A = 6,000,000 J.




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