What work should be done when moving 0.25m of a conductor 0.4m

What work should be done when moving 0.25m of a conductor 0.4m long with a current of 21A in a uniform magnetic field with an induction of 1.2T?

To find out the work done when moving the specified conductor, use the formula: A = F * S = FA * S * cosα = B * I * l * sinβ * S * cosα (we assume that sinβ = 1 and sinα = 1).

Data: B – induction (B = 1.2 T); I is the current in the conductor (I = 21 A); l is the length of the conductor (l = 0.4 m); S – displacement (S = 0.25 m).

Calculation: A = B * I * l * S = 1.2 * 21 * 0.4 * 0.25 = 2.52 J.

Answer: In order to move the specified conductor by 0.25 m, work of 2.52 J must be performed.