What work was done in the conductor with an electric current of 800 mA in 2 minutes

What work was done in the conductor with an electric current of 800 mA in 2 minutes if the voltage at the ends of the conductor is 20 V?

These tasks: I (current in the conductor) = 800 mA; t (time of movement of electric current through the conductor) = 2 min; U (voltage at the ends of the conductor) = 20 V.

SI system: I = 800 mA = 800 * 10-3 A; t = 2 min = 120 s.

The work done by the electric current in the conductor can be calculated using the formula: A = U * I * t.

Let’s make a calculation: A = 20 * 800 * 10-3 * 120 = 1920 J.

Answer: The work of 1920 J. was performed by electric current in the conductor.