What work will be done by the current in the electric motor in 90 s, if at a voltage of 220 V

What work will be done by the current in the electric motor in 90 s, if at a voltage of 220 V the current in the motor winding is 0.2A?

Initial data: t (operating time of the current in the electric motor) = 90 s; U (voltage on the electric motor) = 220 V; I (current in the motor winding) = 0.2 A.

The work that the current in the electric motor can do is determined by the formula: A = U * I * t.

Calculation: A = 220 * 0.2 * 90 = 3960 J or 3.96 kJ.

Answer: In 90 seconds, the current in the electric motor can do the work of 3.96 kJ.



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