When 1.3 g of zinc reacts with sulfuric acid, gas is released. Determine its volume.

1. As an active metal, zinc displaces hydrogen from acid solutions, in this case the reaction has the form:

Zn + H2SO4 = ZnSO4 + H2 ↑;

2. Let’s calculate the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 1.3: 65 = 0.02 mol;

3. Set the amount of released hydrogen:

n (H2) = n (Zn) = 0.02 mol;

4. Determine the volume of hydrogen:

V (H2) = n (H2) * Vm = 0.02 * 22.4 = 0.448 l.

Answer: 0.448 l.