When 1 mol of oxygen is burned in an excess of hydrogen, 484 kJ of heat is released (Q = +484 kJ).

When 1 mol of oxygen is burned in an excess of hydrogen, 484 kJ of heat is released (Q = +484 kJ). When 1 mol of ozone is burned in an excess of hydrogen, 870 kJ is released (Q = +870 kJ). Calculate the thermal effect (taking into account the sign) of obtaining 1 mole of oxygen from ozone.

Given:
1 mole of oxygen O2 flares up, then
484 kJ of heat is released, that is, Q = + 484 * 10 to the power of 3 J
1 mole of ozone flares up, then
870 kJ is allocated, that is, Q = + 870 * 10 to the power of 3 J
find the thermal effect of obtaining 1 mole of oxygen from ozone.
Decision:
Heat effect value = 2 moles of hydrogen
volume = 22.4 l / mol * 2 mol = 48.4 liters
then we get
44.8 liters of hydrogen – 484 * 10 to the power of 3 J
5, 6 liters of hydrogen – X * 10 to the power of 3 J
then X = 5.6 l * 484 * 10 in the degree of 3 J / 4 4, 8 * 10 in the degree of 3 J = 5.6 * 484/44, 8 = 60.5 * 10 in the degree of 3 J = 60.5 kj