When 11 2 g of iron reacted with hydrochloric acid, 4.48 l of hydrogen were released.

When 11 2 g of iron reacted with hydrochloric acid, 4.48 l of hydrogen were released. Calculate the volume fraction of the yield of hydrogen from the theoretically possible

Let’s execute the solution:

According to the condition of the problem, we compose the equation of the process:
2Fe + 6HCl = 2FeCl3 + 3H2 – OBP, hydrogen is evolved.

We make calculations:
M (Fe) = 55.8 g / mol;

M (H2) = 2 g / mol;

Y (Fe) = m / M = 11.2 / 55.8 = 0.2 mol.

Proportion:
0.2 mol (Fe) – X mol (H2);

-2 mol – 3 mol from here, X mol (H2) = 0.2 * 3/2 = 0.3 mol.

We find the output of the product:
V (H2) = 0.3 * 22.4 = 6.72 liters (theoretical volume);

W = 4.48 / 6.72 * 100 = 66.6%

Answer: the hydrogen yield is 66.6%