When 11.2 g of potassium hydroxide interacts with phosphoric acid, a salt is formed, determine its mass.

1. Let’s compose the equation of the reaction proceeding during the interaction of potassium hydroxide with phosphoric acid:

3KOH + H3PO4 = K3PO4 + 3H2O;

2. Let’s calculate the chemical amount of the reacted potassium hydroxide:

n (KOH) = m (KOH): M (KOH);

M (KOH) = 39 + 16 + 1 = 56 g / mol;

n (KOH) = 11.2: 56 = 0.2 mol;

3. Set the amount of potassium phosphate formed:

n (K3PO4) = n (KOH): 3 = 0.2: 3 = 0.0667 mol;

4. Determine the mass of salt:

m (K3PO4) = n (K3PO4) * M (K3PO4);

M (K3PO4) = 39 * 3 + 31 + 4 * 16 = 212 g / mol;

m (K3PO4) = 0.0667 * 212 = 14.14 g.

Answer: 14.14 g.