When 12.8 g of alcohol react with sodium, 4.48 liters of hydrogen are formed. what alcohol?

Let’s carry out the solution, draw up the general formula of alcohol: R-OH;
Let’s write schematically the process of interaction of alcohol with sodium:
2ROH + 2Na = 2RONa + H2 – substitution reaction, hydrogen gas is released.
Determine the number of moles of hydrogen:
1 mol of gas at n. y – 22.4 l;
X mol (H2) – 4.48 liters. hence, X mol (H2) = 1 * 4.48 / 22.4 = 0.2 mol;
X mol (ROH) – 0.2 mol (H2);
-2 mol -1 mol hence, X mol (ROH) = 2 * 0.2 / 1 = 0.4 mol;
Let’s calculate the molar mass of alcohol:
M = m / Y = 12.8 / 0.4 = 32 g / mol;
General formula of alcohol: CnH2n + 1OH;
12n + 2 + 1 + 16 + 1 = 32;
12n = 32 – 20;
12n = 12;
n = 1;
Molecular formula of alcohol: CH3OH;
M (CH3OH) = 12 + 1 * 3 + 16 +1 = 32 g / mol;
Answer: CH3OH – methanol.