When 120 g of 20% sulfuric acid solution interacted with barium hydroxide solution, a precipitate was formed

When 120 g of 20% sulfuric acid solution interacted with barium hydroxide solution, a precipitate was formed. Calculate the mass of the sediment if the practical yield is 97% of the theoretically possible value.

1. We write down the reaction equation:

H2SO4 + Ba (OH) 2 = BaSO4 ↓ + 2H2O;

2.calculate the mass of sulfuric acid:

m (H2SO4) = w (H2SO4) * m (solution);

m (H2SO4) = 0.2 * 120 = 24 g;

3. find the theoretical chemical amount of sulfuric acid:

ntheor (H2SO4) = m (H2SO4): M (H2SO4);

M (H2SO4) = 2 + 32 + 4 * 16 = 98 g / mol;

ntheor (H2SO4) = 24: 98 = 0.245 mol;

4.According to the equation of the ongoing reaction, the theoretical amount of barium sulfate:

ntheor (BaSO4) = ntheor (H2SO4) = 0.245 mol;

5. find the practical amount of sediment:

npract (BaSO4) = ntheor (BaSO4) * ν = 0.245 * 0.97 = 0.23765 mol;

6.Calculate the mass of the sediment:

m (BaSO4) = ntract (BaSO4) * M (BaSO4);

M (BaSO4) = 137 + 32 + 4 * 16 = 233 g / mol;

m (BaSO4) = 0.23765 * 233 = 55.37 g.

Answer: 55.37 g.



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