When 120 grams of acetic acid was reacted with methanol, 130 grams of ether were obtained.

When 120 grams of acetic acid was reacted with methanol, 130 grams of ether were obtained. What percentage is that of the theoretically possible?

Let’s implement the solution:

According to the condition of the problem, we will write the data:

CH3COOH + CH3OH = CH3COO – CH3 + H2O – esterification, methyl acetate was formed.

Calculations:
M (CH3COOH) = 60 g / mol;

M (ether) = 74 g / mol;

Y (CH3COOH) = m / M = 120/60 = 2 mol;

Y (ether) = 2 mol since the amount of substances is 1 mol.

We find the output of the product:
m (ether) = Y * M = 2 * 74 = 148 g;

W (ether) = m (practical) / m (theoretical) * 100;

W (ether) = 130/148 * 100 = 87.8%

Answer: the yield of methyl ester of acetic acid is 87.8%