When 13 g of limestone containing calcium carbonate interacted with a solution of hydrochloric acid, 2.24

When 13 g of limestone containing calcium carbonate interacted with a solution of hydrochloric acid, 2.24 liters of carbon monoxide were released 4. Determine the mass fraction of impurities in the limestone.

1. Let’s compose the equation of the reaction of interaction of limestone with hydrochloric acid:

CaCO3 + 2HCl = CaCl2 + H2O + CO2;

1. Let’s find the amount of substance in carbon monoxide (4):

2.24 / 22.4 = 0.1 mol;

1. The amount of substance in limestone (calcium carbonate) is 0.1 mol, since the coefficients for it and for carbon dioxide are equal.

2. Let’s find the molecular weight of limestone:

40 + 12 + 16 * 3 = 100 g / mol;

1. Let’s find a mass of pure limestone:

100 * 0.1 = 10 grams;

1. Mass fraction of impurities is equal to:

(13 – 10) / 13 = 3/13 = 0.231 (23.1%);

Answer: the mass fraction of impurities in limestone is 23.1%.