When 15 g of magnesium alloy was diluted in excess with sulfuric acid, 10 liters of hydrogen were formed

When 15 g of magnesium alloy was diluted in excess with sulfuric acid, 10 liters of hydrogen were formed (under normal conditions). Determine the undissolved mixtures in the magnesium alloy.

Magnesium interacts with sulfuric acid. In this case, magnesium sulfate is synthesized and hydrogen gas is released. This reaction is described by the following chemical reaction equation:

Mg + H2SO4 = MgSO4 + H2;

In accordance with the coefficients of the equation, upon dissolution of 1 mol of magnesium, 1 mol of gaseous hydrogen is released.

Let’s calculate the chemical amount in 15 grams of magnesium. To do this, divide the available weight of the metal by the weight of 1 mole of metal.

M Mg = 24 grams / mol;

N Mg = 15/24 = 0.625 mol;

The same amount of hydrogen will be synthesized.

Let’s calculate its volume, for this we multiply the amount of substance by the volume of 1 mole of gas (22.4 liters):

V H2 = 0.625 x 22.4 = 14 liters;

The magnesium content is:

K = 10/14 = 0.714 = 71.4%;