When 16 g of sulfur reacts with oxygen, sulfur oxide (lV) is formed. Find its mass.

Let’s compose the reaction equation: S + O2 = SO2
According to the periodic table, we determine the molar mass of sulfur M (S) = 32 g / mol and its oxide M (SO2) = 32 + 16 * 2 = 64 g / mol.
Using the formula, we find the amount of sulfur substance: n = m / M = 16 g / 32 g / mol = 0.5 mol.
According to the reaction equation, from 1 mol of sulfur, 1 mol of oxide is obtained, therefore n (S) = n (SO2) = 0.5 mol.
Find the mass of the oxide: m = n * M = 0.5 mol * 64 g / mol = 32 g.
Answer: the mass of oxide is 32 g.