When 18 g of propanol reacted with acetic acid, an ester was formed. Find the mass of the ether.

1. The interaction of propanol with acetic acid proceeds according to the equation:

C3H7OH + CH3COOH → CH3COOC3H7 + H2O;

2. Calculate the chemical amount of propanol:

n (C3H7OH) = m (C3H7OH): M (C3H7OH);

M (C3H7OH) = 3 * 12 + 7 + 17 = 60 g / mol;

n (C3H7OH) = 18: 60 = 0.3 mol;

3. Determine the amount of the obtained propane ester of acetic acid:

n (CH3COOC3H7) = n (C3H7OH) = 0.3 mol;

4. Let’s find the mass of the ether:

m (CH3COOC3H7) = n (CH3COOC3H7) * M (CH3COOC3H7);

M (CH3COOC3H7) = 12 + 3 + 12 + 32 + 3 * 12 + 7 = 102 g / mol;

m (CH3COOC3H7) = 0.3 * 102 = 30.6 g.

Answer: 30.6 g.