When 2.8 grams of ethylene react with hydrogen, a product is formed, the mass of which is.

Let’s find the amount of ethylene substance C2H4.

n = m: M.

M (C2H4) = 28 g / mol.

n = 2.8 g: 28 g / mol = 0.1 mol.

Let’s compose the reaction equation. Let’s find the quantitative ratios of substances.

C2H4 + H2 → C2H6

According to the reaction equation, there is 1 mol of C2H6 for 1 mol of C2H4. Substances are in quantitative ratios 1: 1.

n (C2H4) = n (C2H6) = 0.1 mol.

Let’s find the mass of C2H6.

M (C2H6) = 30 g / mol.

m = n × M.

m = 30 g / mol × 0.1 mol = 3 g.

Answer: 3 y.