When 20 g of phenol interacted with 15 g of sodium, a gas was formed, calculate its volume?

Let’s execute the solution:

Let’s write down the data on the condition of the problem:
m = 20 g m = 15 g X l -?

2С6Н5ОН + 2Na = 2C6H5ONa + H2 – substitutions, hydrogen is released.

Calculations:
M (C6H5OH) = 64 g / mol;

M (Na) = 22.9 g / mol.

Let’s determine the amount of starting substances:
Y (C6H5OH) = m / M = 20/64 = 0.3 mol (deficient substance);

Y (Na) = m / M = 15 / 22.9 = 0.7 mol (substance in excess).

Calculations are made for the substance in deficiency.

Proportion:
0.3 mol (C6H5OH) – X mol (H2);

-2 mol -1 mol hence, X mol (H2) = 0.3 * 1/2 = 0.15 mol.

Find the volume of the product:
V (H2) = 0.15 * 22.4 = 3.36 L

Answer: the volume of hydrogen is 3.36 liters.