When 20 grams of calcium reacted with an excess of hydrochloric acid, 140 liters of hydrogen were released under normal
| November 16, 2020 | education
When 20 grams of calcium reacted with an excess of hydrochloric acid, 140 liters of hydrogen were released under normal conditions, calculate the volume fraction of the reaction products.
Ca + 2HCL (IZB) = CACL2 + H2
m (Ca) = 20g
m (H) = 140l
n (Ca) = m / M = 20/40 = 0.5 mol
n (CaCl2) = n (Ca)
m (CaCl2) = n • M = 0.5 • 111 = 55.5g
W (CaCl2) = 55.5 / 20 = 3%
Answer 3% (H2 does not count, because it is gas)
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