When 23 g of formic acid (CH2O2) were reacted with magnesium shavings taken in excess, 5.1

When 23 g of formic acid (CH2O2) were reacted with magnesium shavings taken in excess, 5.1 liters of hydrogen were obtained. Calculate the volume fraction of the reaction product yield.

Let’s execute the solution:

2COOH + Mg = (HCOO) 2Mg + H2 – substitution, hydrogen is evolved;
Calculations by formulas:
M (CH2O2) = 46 g / mol;

M (H2) = 2 g / mol.

Determine the amount of the original substance:
Y (CH2O2) = m / M = 23/46 = 0.5 mol.

0.5 mol (CH2O2) – X mol (H2);

-2 mol -1 mol hence, X mol (H2) = 0.5 * 1/2 = 0.25 mol.

We find the volume and yield of the product:
V (H2) = 0.25 * 22.4 = 5.6 l (theoretical volume);

Volumetric product yield: V (practical) / V (theoretical) * 100 = 5.1 / 5.6 * 100 = 91.07%

Answer: the volume fraction of hydrogen yield is 91.07%