When 23 g of sodium, containing 10% impurities, interacted with water, 9.072 liters of gas were obtained.

When 23 g of sodium, containing 10% impurities, interacted with water, 9.072 liters of gas were obtained. Determine the practical gas yield in this reaction.

1) Let’s compose the reaction equation: 2Na + 2H2O ==> H2 ^ + 2NaOH
2) Determine the mass of pure sodium: m (na) = 23g * 0.9 = 20.7g
3) Determine the amount of sodium (n (Na)): n (na) = 20.7 / 23 = 0.9 mol According to the reaction equation, it follows that: n (Na): n (H2) = 2: 1 = 0, 45 mol
4) Determine the practical gas output: V pr (H2) = 0.45 x 22.4 = 10.08 l
Answer: V pr (H2) = 10.08 liters.