When 230 g of sodium interacted with water, 100 l of hydrogen were released, determine the yield of the product.

The reaction of sodium with water is described by the following chemical reaction equation:

Na + H2O = NaOH + 1/2 H2;

When reacted from one mole of sodium, it forms half a mole of hydrogen.

Let’s find the theoretical volume of hydrogen.

M Na = 23 grams / mol;

N Na = 230/23 = 10 mol;

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

V H2 = 10 x 22.4 = 224 liters;

The product yield will be equal to the ratio of practical and theoretical volume and will be:

K = 100/224 = 0.4464 = 44.64%;