When 28 g of active monovalent metal were dissolved in water, 4 g of hydrogen were released.
| December 3, 2020 | education
When 28 g of active monovalent metal were dissolved in water, 4 g of hydrogen were released. Determine which metal was dissolved in water
2Me + 2H2O = 2MeOH + H2
n (H2) = m \ M = 4 \ 2 = 2 mol
according to the reaction equation n (Me) = 2 * 2 = 4 mol
M (Me) = m \ n = 28 \ 4 = 7 g \ mol
Me = Li
Answer: metal – lithium
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