When 30 g of hydrochloric acid interacts with zinc, hydrogen is released.

When 30 g of hydrochloric acid interacts with zinc, hydrogen is released. Find the mass of the amount of the substance and the volume of hydrogen.

Zinc reacts with hydrochloric acid to release hydrogen gas and form zinc chloride:

Zn + 2HCl = ZnCl2 + H2;

1 mole of zinc reacts with 2 moles of acid. In this case, 1 mol of salt is formed and 1 mol of hydrogen gas is released.

Let’s calculate the chemical amount of a substance in 30 grams of hydrochloric acid. To do this, divide the weight of the substance by the weight of 1 mole of the substance.

M HCl = 1 + 35.5 = 36.5 grams / mol; N HCl = 30 / 36.5 = 0.822 mol;

When reacting with such an amount of acid, 2 times less hydrogen will be synthesized.

Let’s calculate the volume of hydrogen. To do this, multiply the amount of substance by the volume of 1 mole of gas, which is 22.4 liters.

N H2 = 0.822 / 2 = 0.411 mol; V H2 = 0.411 x 22.4 = 9.21 liters;

Let’s calculate the weight of hydrogen. To do this, multiply the amount of substance by the weight of 1 mole of gas, which is 2 grams / mole.

M H2 = 2 grams / mol; m H2 = 0.411 x 2 = 0.822 grams;