When 4 mol of aluminum reacted with hydrochloric acid, hydrogen was formed.

When 4 mol of aluminum reacted with hydrochloric acid, hydrogen was formed. Determine the amount of hydrogen substance.

Aluminum enters into an active reaction with hydrochloric acid. This forms an aluminum chloride salt and releases hydrogen gas. The interaction is described by the following chemical equation.

Al + 3HCl = AlCl3 + 3/2 H2;

N Al = 4 mol;

The chemical amount of released hydrogen will be: 4 x 3/2 = 6 mol

Let’s calculate its volume.

To do this, multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 6 x 22.4 = 134.4 liters;